2. In
1Dial needle B moves 1/12 the Dial Distance (D_{F}). Needle R move 1
full Dial Distance (D_{F}). And travels 100.5 mm (32mm x
3.1416 = 100.5312 ≈ 100.5mm) on the Distance Piece which represents 1669.7916 km
moved by the Equator. Using here 1/12 Dial Distance (D_{F}) moved by
Needle B =1/12 Dial distance (D_{F}) as D _{F}1/12 _{B
}i.e. Needle R= 1Dial Distance (D_{F}) as D_{R} (=1Basic
{B}) we have the speed of:

a.
Car W’s Speed = 20Chkm/(D_{F}R-60) which would read as 20Chkm per
Dial (D_{F}) (full Dial Travel by Needle R) If this Speed is
constant & has a definite Direction then it would be Car W’s Velocity
=20Chkm/D_{F}R-60.

b. Car
Y’s Speed=40Chkm/D_{F}R-60 which would read as 40Chkm per Dial
(D_{F}) (full Dial travel by needle R) If it is constant & has a
definite direction then speed becomes Car Y’s velocity
=40Chkm/D_{F}R-60.

c.
Car Z’ Speed =60Chkm/D_{F}R-60 which would read as 60Chkm per
Dial (D_{F}) (full Dial travel by needle R) If it is constant & has
a definite direction then Speed becomes Car Z’s velocity
=60Chkm/D_{F}R-60.

Here we see that the Speed/Velocity of Car W is ½ of Car Y and 1/3 of Car Z.

^{
}

__Needle P
moves D _{F}P-1 of D_{F}R-1/60 the Dial which is 1P__

** **

A Body which
starts with a velocity of 3Chm/P and Travels with an acceleration of
2Chm/P^{2} (Chm /P/P = Chm/P^{2}) for 4 P’s. At the end of the
1^{st} P, 2Chm/P is added to 3Chm/P and the body at the end of the
1^{st} Portion attains the velocity of 3Chm/P + 2Chm/P = 5Chm/P. As
such, Velocities attained by the body starting with an original velocity of
3Chm/P and travelling with an Acceleration of 2Chm/P^{2} for 4P’s would
be as shown below-

__Starting Velocity of 3Chm/P. Acceleration
2Chm/P ^{2} for 4P__

At the end
of 1^{st} Portion 3Chm/P
__+2Chm/P__=5Chm/P

At the end
of 2^{nd }Portion 3Chm/P+
__2Chm/P+2Chm/P__=7Chm/P

At the end
of 3^{rd }Portion 3Chm/P+ __2Chm/P
+2Chm/P +2Chm/P__ = 9Chm/P

At the end of 4^{th
} Portion 3Chm/P+^{ }__2Chm/P +
2Chm/P+2Chm/P +2Chm/P__=11Chm/P^{
}

^{}

So we have
** Acceleration **according to the New Concept which
is =

and we
know __Force =Mass x Acceleration or F = M
x
Chm/P ^{2}
__

__Work =
Force x Distance ; W=F x D ; W = ( M x Chm/P ^{2 }) x D ; And the
Capacity to do Work is Energy and Mechanical Power
as - Horse Power ( H. P.) __

__(
Metric- “ Pferdestaerke “) 1PS = 75kpm/s ____( i.e. 75kp x
1m) ¸1s__

__would
become according to the new concept -75kpm/P = 75kp . m / P__

__kp x
Chm x 75 ¸
0.463831/P = 161.69682 kpChm/P__

__( Metric
New Concept ) 1PS_{NC} __

__Needle
movements on Distance Piece.__

See Fig.7,
page 14. We have Chosen a Diameter =19.1mm which multiplied by 3.1416 gives us
60mm Circumference. These Dials (D_{F})with their respective Needle
movements have been shown below i.e.

**(47)**