Some calculations of Physics problems by conventional methods - alongside by the New Concept Method.
a If a body is moving with a uniform velocity of 40 m/s, how far will it go in two minutes? [Problem 1 (Pg-31) I.C.S.E.]
Solution
Conventional method New Concept Method
v = 40m/s v = 40 Chm/P
t = 2minutes = 2 x 60 seconds Dial Distance = 2 R = 2 x 60 P
= 120 seconds = 120 P
S = v x t S = v x Dial Distance
= 40 x 120 = 4800 meters = 40 x 120 = 4800 Ch meters
= 4 km 800 meters = 4 Ch Km 800 Ch meters
Acceleration
Conventional method New Concept Method
Acceleration = Change in Velocity Change in Distance/Dial (DF)
Time Taken Dial Distance (DF)
Distance Distance
= Time = Dial (DF)
Time Dial (DF)
= Distance Distance
Time x time Dial (DF) x Dial (DF)
= Distance = Distance
Time2 (Dial DF) 2
= Distance/Time2 = Distance/ (Dial DF) 2
b. A body starts moving from rest with an acceleration of 5m/s2. How far will it go in 1 minute? [Problem 5 (Pg-32) I.C.S.E.]
Solution
Conventional method New Concept Method
u = 0, a = 5 m/s2 u = 0, a = 5Chm/P2
t = 1 minute = 60 seconds Dial DF= 1R = 60 P
S = ut + ½ at2= 0 x 60 + ½ x 5 x 60 x 60 = 0x60P + ½ x 5 x 60P x 60P
= 0 + 9000 m = 0 + 9000 Ch meters
=9km = 9ChotuKm
(53)